rust Clean way to get Option::unwrap_or_else behaviour with an Option<&T>
You can use the map
method in combination with the unwrap_or_else
method to achieve a similar behavior with an Option<&T>
in Rust. Here's an example:
let option_value: Option<&T> = Some(&value);
let default_value: T = / your default value here /;
let result = option_value.map(|v| *v).unwrap_or_else(|| default_value);
In this code snippet, we first use the map
method on option_value
to transform the Option<&T>
to an Option<T>
by dereferencing the reference v
inside the closure. Then, we call unwrap_or_else
on the resulting Option<T>
, providing a closure that returns default_value
if the option is None
.
This approach allows you to handle the case where option_value
is Some
by unwrapping the inner value and using it, and handle the case where it is None
by providing a default value.
Let me know if you need further assistance!