Find unique element in array where all other elements occur 3 times, uses boolean logic
Finding Unique Element in an Array Using Boolean Logic in Rust
To find the unique element in an array where all other elements occur three times using boolean logic in Rust, you can utilize bitwise operations. One possible approach is to iterate through the array and count the number of occurrences of each element using a hashmap. Then, iterate through the hashmap and return the element with a count of one.
Here's an example implementation:
use std::collections::HashMap;
fn find_unique_element(arr: &[u32]) -> Option<u32> {
let mut count_map: HashMap<u32, u32> = HashMap::new();
// Count the occurrences of each element
for &num in arr {
*count_map.entry(num).or_insert(0) += 1;
}
// Find the element with a count of one
for (&num, &count) in count_map.iter() {
if count == 1 {
return Some(num);
}
}
None
}
fn main() {
let arr = [1, 2, 3, 4, 5, 1, 2, 3, 4, 1, 2, 3];
let unique_element = find_unique_element(&arr);
match unique_element {
Some(num) => println!("Unique element: {}", num),
None => println!("No unique element found"),
}
}
In this example, the find_unique_element
function takes an array arr
as input and returns an Option<u32>
representing the unique element found. If a unique element is found, it is returned as Some(num)
, otherwise None
is returned.
Please note that this is just one possible implementation and there may be other approaches to solve this problem.