rust prime factorization with struct

Here's an example of how you can implement prime factorization using a struct in Rust:

struct PrimeFactorizer {
    num: u64,
}

impl PrimeFactorizer {
    fn new(num: u64) -> Self {
        PrimeFactorizer { num }
    }

    fn factorize(&self) -> Vec<u64> {
        let mut factors = Vec::new();
        let mut num = self.num;
        let mut divisor = 2;

        while divisor <= num {
            if num % divisor == 0 {
                factors.push(divisor);
                num /= divisor;
            } else {
                divisor += 1;
            }
        }

        factors
    }
}

fn main() {
    let factorizer = PrimeFactorizer::new(60);
    let factors = factorizer.factorize();
    println!("Prime factors: {:?}", factors);
}

In this code, we define a struct called PrimeFactorizer that holds a single field num of type u64, representing the number we want to factorize. We then implement a method new that allows us to create a new instance of PrimeFactorizer and initialize the num field.

The factorize method is where the prime factorization logic is implemented. It initializes an empty vector factors to store the prime factors. We then iterate from divisor = 2 up to num, checking if num is divisible by divisor. If it is, we add divisor to the factors vector and divide num by divisor. If it's not divisible, we increment divisor by 1. This process continues until divisor is greater than num.

In the main function, we create a PrimeFactorizer instance with the number 60 and call the factorize method to obtain the prime factors. Finally, we print the prime factors using println!.

Note: This code assumes that the number provided for factorization is greater than 1. It may not work correctly for numbers less than or equal to 1.