how to find even number in an array ruby

To find even numbers in an array in Ruby, you can follow these steps:

1. Initialize an empty array: Create an empty array to store the even numbers that are found in the input array.

2. Iterate over the input array: Use a loop to go through each element in the input array.

3. Check if the number is even: For each element in the array, use the modulo operator (%) to check if it is divisible by 2 without any remainder. If the remainder is 0, then the number is even.

4. Add even numbers to the result array: If a number is even, append it to the result array that was initialized in step 1.

5. Return the result array: After iterating through all the elements in the input array, return the result array that contains the even numbers.

Here is an example code snippet that demonstrates these steps:

def find_even_numbers(array)
  result = []
  array.each do |number|
    if number % 2 == 0
      result << number
    end
  end
  return result
end

# Example usage:
numbers = [1, 2, 3, 4, 5, 6]
even_numbers = find_even_numbers(numbers)
puts even_numbers

In this example, the find_even_numbers method takes an array as an argument and returns a new array containing the even numbers. The each method is used to iterate over each element in the input array, and the modulo operator (%) is used to check if each number is even. If a number is even, it is added to the result array. Finally, the result array is returned and printed using puts.