drop haskell
In Haskell, the drop
function is used to remove a specified number of elements from the beginning of a list and return the remaining elements. The drop
function takes two arguments: the number of elements to drop and the list from which to drop the elements.
Here's the syntax for the drop
function:
drop :: Int -> [a] -> [a]
The first argument is of type Int
and represents the number of elements to drop. The second argument is of type [a]
, which denotes a list of elements of any type a
. The drop
function returns a new list [a]
that contains the remaining elements after dropping the specified number of elements from the beginning.
Here's an example usage of the drop
function:
drop 3 [1, 2, 3, 4, 5] -- returns [4, 5]
In this example, the drop
function is called with the arguments 3
and [1, 2, 3, 4, 5]
. It drops the first three elements from the list and returns [4, 5]
.
Note that if the specified number of elements to drop is greater than the length of the list, an empty list []
is returned.
I hope this clarifies the usage of the drop
function in Haskell!