drop haskell

In Haskell, the drop function is used to remove a specified number of elements from the beginning of a list and return the remaining elements. The drop function takes two arguments: the number of elements to drop and the list from which to drop the elements.

Here's the syntax for the drop function:

drop :: Int -> [a] -> [a]

The first argument is of type Int and represents the number of elements to drop. The second argument is of type [a], which denotes a list of elements of any type a. The drop function returns a new list [a] that contains the remaining elements after dropping the specified number of elements from the beginning.

Here's an example usage of the drop function:

drop 3 [1, 2, 3, 4, 5] -- returns [4, 5]

In this example, the drop function is called with the arguments 3 and [1, 2, 3, 4, 5]. It drops the first three elements from the list and returns [4, 5].

Note that if the specified number of elements to drop is greater than the length of the list, an empty list [] is returned.

I hope this clarifies the usage of the drop function in Haskell!