golang sort strings by length

To sort strings by length in Go, you can use the built-in sort package and implement the sort.Interface interface. Here are the steps to achieve this:

1. Create a custom type that represents the slice of strings you want to sort. Let's call it ByLength.
2. Implement the Len(), Swap(), and Less() methods on the ByLength type. These methods define the sorting behavior.
3. In the Len() method, return the length of the slice.
4. In the Swap() method, swap the strings at the given indices.
5. In the Less() method, compare the lengths of the strings at the given indices and return true if the length of the string at index i is less than the length of the string at index j, and false otherwise.
6. Finally, use the sort.Sort() function, passing in an instance of ByLength, to sort the strings by length.

Here is an example code snippet to demonstrate the above steps:

package main

import (
    "fmt"
    "sort"
)

// Define custom type
type ByLength []string

// Implement sorting methods
func (s ByLength) Len() int           { return len(s) }
func (s ByLength) Swap(i, j int)      { s[i], s[j] = s[j], s[i] }
func (s ByLength) Less(i, j int) bool { return len(s[i]) < len(s[j]) }

func main() {
    // Create a slice of strings
    strings := []string{"banana", "apple", "cherry", "date"}

    // Sort the strings by length
    sort.Sort(ByLength(strings))

    // Print the sorted strings
    fmt.Println(strings)
}

When you run this code, the output will be: [date apple banana cherry]. The strings are sorted in ascending order based on their length.

I hope this explanation helps! Let me know if you have any further questions.