golang round float to number of ditigs precision

To round a float to a specific number of digits precision in Go (Golang), you can use the math.Round() function along with the math.Pow() function. Here's an example code snippet that demonstrates this:

package main

import (
    "fmt"
    "math"
)

func main() {
    number := 3.14159265359
    precision := 3

    roundedNumber := math.Round(number*math.Pow(10, float64(precision))) / math.Pow(10, float64(precision))

    fmt.Println(roundedNumber)
}

In this example, we have a variable number which holds the float value that we want to round. The variable precision determines the number of digits precision we want to round the float to.

To round the float, we multiply it by 10 raised to the power of the precision. This shifts the decimal point to the right by precision number of places. We then use the math.Round() function to round the resulting value to the nearest whole number.

After rounding, we divide the rounded value by 10 raised to the power of the precision to shift the decimal point back to its original position.

In the example code snippet, the output will be 3.142, which is the rounded value of 3.14159265359 with a precision of 3 digits.