c++ print array of arrays with pointer

To print an array of arrays in C++ using pointers, you can follow these steps:

1. Declare and initialize your array of arrays. In this example, let's say we have a 2D array of integers with dimensions rows and columns: cpp int arr = new int*[rows]; for (int i = 0; i < rows; i++) { arr[i] = new int[columns]; }

2. Populate the array with values. You can use nested loops to iterate through each element and assign a value. For example: cpp for (int i = 0; i < rows; i++) { for (int j = 0; j < columns; j++) { arr[i][j] = i + j; // Assigning a value to each element } }

3. Print the array of arrays using pointers. You can use nested loops again to iterate through each element and print its value. For example: cpp for (int i = 0; i < rows; i++) { for (int j = 0; j < columns; j++) { cout << arr[i][j] << " "; // Printing each element } cout << endl; // Moving to the next line after each row }

4. Deallocate the memory. Since you allocated memory dynamically using new, it's important to free it to avoid memory leaks. You need to deallocate both the arrays and the array of pointers. For example: cpp for (int i = 0; i < rows; i++) { delete[] arr[i]; // Deallocating each row } delete[] arr; // Deallocating the array of pointers

Here is the complete code snippet:

#include <iostream>
using namespace std;

int main() {
    int rows = 3;
    int columns = 4;

    int arr = new int*[rows];
    for (int i = 0; i < rows; i++) {
        arr[i] = new int[columns];
    }

    for (int i = 0; i < rows; i++) {
        for (int j = 0; j < columns; j++) {
            arr[i][j] = i + j;
        }
    }

    for (int i = 0; i < rows; i++) {
        for (int j = 0; j < columns; j++) {
            cout << arr[i][j] << " ";
        }
        cout << endl;
    }

    for (int i = 0; i < rows; i++) {
        delete[] arr[i];
    }
    delete[] arr;

    return 0;
}

This code will create a 2D array, populate it with values, print the array, and then deallocate the memory to avoid memory leaks.