divisor summation
#include <iostream>
using namespace std;
int sumOfDivisors(int n) {
int sum = 1; // Initialize sum with 1 as every number is divisible by 1
for (int i = 2; i <= n / 2; ++i) {
if (n % i == 0) {
sum += i;
}
}
return sum;
}
int main() {
int num;
cout << "Enter a positive integer: ";
cin >> num;
cout << "Sum of divisors of " << num << " is: " << sumOfDivisors(num);
return 0;
}