print the elements of the array without using the [] notation in c++

#include <iostream>

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int size = sizeof(arr) / sizeof(arr[0]);

    for (int i = 0; i < size; i++) {
        std::cout << *(arr + i) << " ";
    }

    return 0;
}

Explanation:

• First, we include the <iostream> library, which provides the input/output stream objects such as std::cout.
• Inside the main() function, we declare an array arr of type int and initialize it with some values {1, 2, 3, 4, 5}.
• We calculate the size of the array by dividing the total size of the array by the size of its first element. This is done using the sizeof() operator.
• Next, we use a for loop to iterate over each element of the array. The loop variable i starts from 0 and goes up to size - 1.
• Inside the loop, we use pointer arithmetic to access each element of the array. The expression *(arr + i) gives us the value at the i-th index of the array.
• Finally, we use std::cout to print each element followed by a space.

Note: The *(arr + i) is equivalent to arr[i] and is used here to demonstrate an alternative way of accessing array elements without using the [] notation.