prime factorisation of a number in c++

Sure! Here is an example of how you can perform prime factorization of a number in C++:

#include <iostream>

void primeFactorization(int n) {
    while (n % 2 == 0) {
        std::cout << 2 << " ";
        n = n / 2;
    }

    for (int i = 3; i * i <= n; i = i + 2) {
        while (n % i == 0) {
            std::cout << i << " ";
            n = n / i;
        }
    }

    if (n > 2)
        std::cout << n << " ";
}

int main() {
    int num;
    std::cout << "Enter a number: ";
    std::cin >> num;

    std::cout << "Prime factors of " << num << " are: ";
    primeFactorization(num);

    return 0;
}

This program takes a number as input and finds its prime factors. Let's go through the steps in the code:

We include the necessary header file iostream to use input/output operations in C++.
We define a function primeFactorization that takes an integer n as a parameter. This function will perform the prime factorization of n and print the prime factors.
Inside the primeFactorization function, we start by checking if the number is divisible by 2. If it is, we repeatedly divide it by 2 and print 2 as a prime factor until it is no longer divisible by 2.
After the above step, we start a loop from 3 to the square root of n and increment by 2 in each iteration (to skip even numbers). We check if n is divisible by i. If it is, we repeatedly divide n by i and print i as a prime factor until it is no longer divisible by i.
Finally, if n is greater than 2, it means that n itself is a prime number. So we print n as a prime factor.
In the main function, we ask the user to enter a number.
We call the primeFactorization function, passing the user input as the argument.
The prime factors of the entered number are printed on the console.
The program ends by returning 0.

I hope this helps! Let me know if you have any further questions.