c++ max of array

#include <iostream>

int main() {
    int arr[] = {5, 3, 8, 2, 9};
    int n = sizeof(arr) / sizeof(arr[0]);
    int max = arr[0];

    for (int i = 1; i < n; i++) {
        if (arr[i] > max) {
            max = arr[i];
        }
    }

    std::cout << "The maximum element in the array is: " << max << std::endl;

    return 0;
}

1. Include the necessary header file iostream for input/output operations.
2. Define the main() function, which is the entry point of the program.
3. Declare an integer array arr with initial values {5, 3, 8, 2, 9}.
4. Calculate the number of elements in the array by dividing the size of the array (sizeof(arr)) by the size of a single element (sizeof(arr[0])). Store the result in an integer variable n.
5. Declare an integer variable max and initialize it with the first element of the array (arr[0]).
6. Start a for loop with an initialization statement (int i = 1) that sets the loop counter variable i to 1. The loop will iterate as long as the condition i < n is true. After each iteration, the loop counter is incremented by 1 (i++).
7. Inside the loop, check if the current element arr[i] is greater than the current maximum max. If it is, update the value of max to the current element.
8. After the loop ends, the variable max will contain the maximum element in the array.
9. Use std::cout to print the message "The maximum element in the array is: " followed by the value of max, and then use std::endl to insert a newline character.
10. Return 0 to indicate successful program execution to the operating system.