how to check sqrt of number is integer c++

To check if the square root of a number is an integer in C++, you can use the sqrt function from the cmath library. Here are the steps to do this:

1. Include the cmath library at the beginning of your code to access the sqrt function.

#include <cmath>

1. Declare a variable to store the number for which you want to check the square root.

int number = 16;

1. Use the sqrt function to calculate the square root of the number.

double squareRoot = sqrt(number);

1. Check if the square root is an integer by comparing it to its rounded value. You can use the round function from the cmath library to round the square root.

if (squareRoot == round(squareRoot)) {
    // The square root is an integer
    // Perform your desired operations here
} else {
    // The square root is not an integer
    // Perform other operations here
}

1. You can repeat this process for different numbers by assigning new values to the number variable and executing the steps above.

Here's the complete code:

#include <iostream>
#include <cmath>

int main() {
    int number = 16;
    double squareRoot = sqrt(number);

    if (squareRoot == round(squareRoot)) {
        std::cout << "The square root is an integer." << std::endl;
    } else {
        std::cout << "The square root is not an integer." << std::endl;
    }

    return 0;
}

This code checks if the square root of the number 16 is an integer. You can modify the number variable to check different numbers.