count bit 1 c++

To count the number of 1 bits in an integer in C++, you can use the bitwise AND operator along with a loop to iterate over the bits of the integer. Here is the step-by-step explanation:

1. Initialize a variable count to 0. This variable will keep track of the number of 1 bits.

2. Use a loop to iterate over each bit of the integer. You can use a for loop that starts from 0 and goes up to the number of bits in the integer.

3. Inside the loop, use the bitwise AND operator (&) to check if the current bit is 1. The bitwise AND operator compares each bit of the integer with 1, and if the bit is 1, the result will be 1.

4. If the result of the bitwise AND operation is 1, increment the count variable by 1.

5. Right shift the integer by 1 bit to move on to the next bit. This can be done using the right shift operator (>>).

6. Repeat steps 3 to 5 until you have iterated over all the bits of the integer.

7. After the loop, the count variable will contain the total number of 1 bits in the integer.

Here is an example code snippet that demonstrates this approach:

int countBits(int num) {
    int count = 0;
    for (int i = 0; i < sizeof(int) * 8; i++) {
        if (num & 1) {
            count++;
        }
        num >>= 1;
    }
    return count;
}

In this example, the function countBits takes an integer num as input and returns the count of 1 bits in the integer. The loop runs for sizeof(int) 8 iterations, where sizeof(int) gives the number of bytes occupied by an integer and 8 gives the number of bits. The bitwise AND operator & is used to check if the current bit is 1, and the right shift operator >> is used to move on to the next bit. The count of 1 bits is incremented whenever a 1 bit is encountered. Finally, the count is returned as the result.

I hope this explanation helps! Let me know if you have any further questions.