c++ get filename from path
To get the filename from a path in C++, you can use the <filesystem>
library, which provides various functions and classes for working with files and directories. Here are the steps to extract the filename from a path:
- Include the
<filesystem>
header:
#include <filesystem>
- Use the
std::filesystem::path
class to represent the path:
std::filesystem::path filePath("path/to/file.txt");
- Use the
filename()
function of thestd::filesystem::path
class to get the filename:
std::string filename = filePath.filename().string();
Let's break down each step:
Step 1: Include the <filesystem>
header
- The <filesystem>
header provides the necessary functions and classes for working with files and directories in C++. Including this header allows you to use the functionalities provided by the library.
Step 2: Use the std::filesystem::path
class to represent the path
- In C++, the std::filesystem::path
class is used to represent file and directory paths. You can create an object of this class by passing the path as a string to its constructor. For example, std::filesystem::path filePath("path/to/file.txt");
creates a filePath
object representing the path "path/to/file.txt".
Step 3: Use the filename()
function of the std::filesystem::path
class to get the filename
- The filename()
function returns the filename component of the path. It removes the directory part of the path and returns only the filename. In the example code, filePath.filename()
returns the filename component of the filePath
object. To convert it to a string, you can use the string()
function. Finally, you can assign the result to a std::string
variable, such as std::string filename = filePath.filename().string();
.
By following these steps, you can extract the filename from a path in C++.