how to find if number is perfect square
#include <iostream>
#include <cmath>
bool isPerfectSquare(int num) {
if (num < 0) {
return false;
}
int root = static_cast<int>(std::sqrt(num));
return (root * root == num);
}
int main() {
int number;
std::cout << "Enter a number: ";
std::cin >> number;
if (isPerfectSquare(number)) {
std::cout << number << " is a perfect square." << std::endl;
} else {
std::cout << number << " is not a perfect square." << std::endl;
}
return 0;
}