Studying Alphabet codechef solution in c++
Here is a step-by-step explanation for the solution to the "Studying Alphabet" problem on CodeChef, implemented in C++:
#include <iostream>
#include <string>
#include <vector>
using namespace std;
int main() {
int t;
cin >> t; // Read the number of test cases
while (t--) {
string s;
cin >> s; // Read the input string
vector<int> freq(26, 0); // Initialize a vector to store the frequency of each alphabet
for (char c : s) {
freq[c - 'a']++; // Increment the frequency of the corresponding alphabet
}
int q;
cin >> q; // Read the number of queries
while (q--) {
int k;
cin >> k; // Read the query
int count = 0;
for (int i = 0; i < 26; i++) {
if (freq[i] > k) {
count += (freq[i] - k); // Increment count by the difference between the frequency and k
}
}
cout << count << endl; // Print the answer for the query
}
}
return 0;
}
Explanation:
We start by including the necessary libraries:
iostream
for input/output,string
for string manipulation, andvector
for storing the frequency of alphabets.The
using namespace std;
statement allows us to use standard library functions and objects without specifying the namespace.The
main()
function is the entry point of the program.We read the number of test cases
t
usingcin >> t;
.We enter a while loop that will execute
t
times. This loop is used to process each test case.Inside the loop, we read the input string
s
usingcin >> s;
.We initialize a vector
freq
of size 26 with all elements set to 0. This vector will be used to store the frequency of each alphabet.We iterate through each character
c
in the input strings
using a range-based for loop.Inside the loop, we increment the frequency of the corresponding alphabet in the
freq
vector. We do this by subtracting the ASCII value of 'a' from the characterc
to get its index in thefreq
vector.Next, we read the number of queries
q
usingcin >> q;
.We enter another while loop that will execute
q
times. This loop is used to process each query.Inside the loop, we read the query value
k
usingcin >> k;
.We initialize a variable
count
to 0. This variable will store the answer for each query.We iterate through each element in the
freq
vector using a for loop.Inside the loop, we check if the frequency of the current alphabet is greater than
k
.If the frequency is greater than
k
, we incrementcount
by the difference between the frequency andk
. This represents the number of times we need to remove an alphabet to make its frequency equal tok
.After processing all the alphabets, we print the value of
count
usingcout << count << endl;
.Once all the queries for a test case are processed, we move to the next test case.
Finally, we return 0 to indicate successful program execution.
I hope this explanation helps! Let me know if you have any further questions.