Calculating Function codeforces in c++
#include <iostream>
int calculateFunction(int n) {
if (n % 2 == 0) {
return n / 2;
} else {
return -((n + 1) / 2);
}
}
int main() {
int n;
std::cin >> n;
std::cout << calculateFunction(n) << std::endl;
return 0;
}
Explanation:
The given code is written in C++ and calculates the value of a function called "calculateFunction". Let's go through each step of the code and understand its functionality.
Library inclusion: The code starts with the inclusion of the
iostream
library, which is required for input/output operations.Function definition: The code defines a function called
calculateFunction
that takes an integern
as a parameter and returns an integer value. This function calculates the value of the function based on the input parametern
.Function implementation: Inside the
calculateFunction
function, there is anif
statement that checks if the inputn
is divisible by 2 without any remainder (i.e., ifn
is an even number). If the condition is true, it executes the code inside theif
block:The function returns the value of
n
divided by 2. This means that ifn
is even, the function will returnn/2
.Else statement: If the condition in the
if
statement is false (i.e., ifn
is an odd number), the code inside theelse
block will be executed:The function returns the value of
-((n + 1) / 2)
. Here,n + 1
is calculated first, then divided by 2, and the result is negated. This means that ifn
is odd, the function will return-(n+1)/2
.Main function: The code then defines the
main
function, which is the entry point of the program.Variable declaration: Inside the
main
function, an integer variablen
is declared to store the user input.Input operation: The code uses
std::cin
to read a value from the user and store it in the variablen
.Function call and output: The code calls the
calculateFunction
function with the inputn
as an argument and prints the returned value usingstd::cout
.End of the program: Finally, the program returns 0 to indicate successful execution.
This code calculates the value of the function based on whether the input is even or odd.