Calculating Function codeforces in c++

#include <iostream>

int calculateFunction(int n) {
    if (n % 2 == 0) {
        return n / 2;
    } else {
        return -((n + 1) / 2);
    }
}

int main() {
    int n;
    std::cin >> n;
    std::cout << calculateFunction(n) << std::endl;
    return 0;
}

Explanation:

The given code is written in C++ and calculates the value of a function called "calculateFunction". Let's go through each step of the code and understand its functionality.

  1. Library inclusion: The code starts with the inclusion of the iostream library, which is required for input/output operations.

  2. Function definition: The code defines a function called calculateFunction that takes an integer n as a parameter and returns an integer value. This function calculates the value of the function based on the input parameter n.

  3. Function implementation: Inside the calculateFunction function, there is an if statement that checks if the input n is divisible by 2 without any remainder (i.e., if n is an even number). If the condition is true, it executes the code inside the if block:

  4. The function returns the value of n divided by 2. This means that if n is even, the function will return n/2.

  5. Else statement: If the condition in the if statement is false (i.e., if n is an odd number), the code inside the else block will be executed:

  6. The function returns the value of -((n + 1) / 2). Here, n + 1 is calculated first, then divided by 2, and the result is negated. This means that if n is odd, the function will return -(n+1)/2.

  7. Main function: The code then defines the main function, which is the entry point of the program.

  8. Variable declaration: Inside the main function, an integer variable n is declared to store the user input.

  9. Input operation: The code uses std::cin to read a value from the user and store it in the variable n.

  10. Function call and output: The code calls the calculateFunction function with the input n as an argument and prints the returned value using std::cout.

  11. End of the program: Finally, the program returns 0 to indicate successful execution.

This code calculates the value of the function based on whether the input is even or odd.