deleting a word with copy fuction c code

Here is an example of C code that deletes a word using the strcpy function:

#include <stdio.h>
#include <string.h>

void deleteWord(char str, const char word) {
    char* found = strstr(str, word);
    if (found != NULL) {
        size_t wordLen = strlen(word);
        memmove(found, found + wordLen, strlen(found + wordLen) + 1);
    }
}

int main() {
    char str[100] = "Hello world! This is a test.";
    const char* word = "world";

    deleteWord(str, word);

    printf("%s\n", str);

    return 0;
}

Explanation:

  1. The code includes the necessary header files stdio.h and string.h which provide the functions and definitions used in the code.

  2. The function deleteWord is defined with two parameters: str which is the string from which the word will be deleted, and word which is the word to be deleted.

  3. Inside the deleteWord function, the strstr function is used to find the first occurrence of the word in the str. The function returns a pointer to the first occurrence of the word in str, or NULL if the word is not found.

  4. If the word is found (found is not NULL), the strlen function is used to determine the length of the word.

  5. The memmove function is then used to move the remaining characters after the word in the str to overwrite the word. The memmove function is used instead of strcpy because it handles overlapping memory regions correctly.

  6. Finally, the main function is defined. It declares a character array str with a size of 100 and initializes it with the string "Hello world! This is a test." It also declares a constant character pointer word which points to the word "world".

  7. The deleteWord function is called with the str and word as arguments to delete the word "world" from the str.

  8. The modified str is then printed using the printf function.

  9. The program returns 0 to indicate successful execution.

I hope this code and explanation help you understand how to delete a word using the strcpy function in C. Let me know if you have any further questions.