armstrong number in c
#include <stdio.h>
int isArmstrong(int num) {
int originalNum, remainder, result = 0, n = 0;
originalNum = num;
while (originalNum != 0) {
originalNum /= 10;
++n;
}
originalNum = num;
while (originalNum != 0) {
remainder = originalNum % 10;
result += pow(remainder, n);
originalNum /= 10;
}
if (result == num)
return 1;
else
return 0;
}
int main() {
int num;
printf("Enter a number: ");
scanf("%d", &num);
if (isArmstrong(num))
printf("%d is an Armstrong number.", num);
else
printf("%d is not an Armstrong number.", num);
return 0;
}
Note: This code calculates whether a given number is an Armstrong number or not.