cout boolalpha

To convert the output of cout to boolalpha in assembly language, you can use the following steps:

1. Load the value to be printed into a register, such as eax.
2. Set the CF flag to indicate that the value is a boolean.
3. Use the adc instruction to add the CF flag to the register.
4. Use the appropriate system call to print the register value.

Here is an example code snippet in x86 assembly language that demonstrates how to achieve this:

section .data
    format db "%s", 0
    value db 0

section .text
    global _start

_start:
    ; Load the value to be printed into a register
    mov eax, 1  ; example value to print

    ; Set the CF flag to indicate that the value is a boolean
    stc

    ; Add the CF flag to the register
    adc eax, 0

    ; Convert the value to a string
    push eax
    push format
    call sprintf
    add esp, 8

    ; Print the value
    push eax
    call printf
    add esp, 4

    ; Exit the program
    mov eax, 1
    xor ebx, ebx
    int 0x80

sprintf:
    push ebp
    mov ebp, esp
    sub esp, 8
    mov eax, [ebp + 8]
    mov edx, [ebp + 12]
    mov ecx, [ebp + 16]
    mov ebx, [ebp + 20]
    push edi
    push esi
    push ebx
    push ecx
    push edx

    mov edi, eax
    mov esi, ecx
    xor eax, eax
    mov ecx, -1
    xor edx, edx

.loop:
    inc ecx
    mov dl, byte [esi + ecx]
    test dl, dl
    jz .end
    cmp dl, '%'
    jne .copy
    mov al, byte [esi + ecx + 1]
    cmp al, '%'
    je .copy

    cmp al, 's'
    jne .copy
    push eax
    mov eax, edi
    push edi
    call _sprintf
    mov edi, eax
    add esp, 8
    jmp .print

.copy:
    mov byte [edi + ecx], dl
    jmp .loop

.print:
    mov eax, 4
    mov ebx, 1
    mov edx, 1
    int 0x80
    jmp .loop

.end:
    pop edx
    pop ecx
    pop ebx
    pop esi
    pop edi
    mov esp, ebp
    pop ebp
    ret

printf:
    push ebp
    mov ebp, esp
    sub esp, 8
    mov eax, [ebp + 8]
    mov edx, [ebp + 12]
    mov ecx, [ebp + 16]
    mov ebx, [ebp + 20]
    push edi
    push esi
    push ebx
    push ecx
    push edx

    mov edi, eax
    mov esi, ecx
    xor eax, eax
    mov ecx, -1
    xor edx, edx

.loop:
    inc ecx
    mov dl, byte [esi + ecx]
    test dl, dl
    jz .end
    cmp dl, '%'
    jne .copy
    mov al, byte [esi + ecx + 1]
    cmp al, '%'
    je .copy

    cmp al, 's'
    jne .copy
    push eax
    mov eax, edi
    push edi
    call _printf
    mov edi, eax
    add esp, 8
    jmp .print

.copy:
    mov byte [edi + ecx], dl
    jmp .loop

.print:
    mov eax, 4
    mov ebx, 1
    mov edx, 1
    int 0x80
    jmp .loop

.end:
    pop edx
    pop ecx
    pop ebx
    pop esi
    pop edi
    mov esp, ebp
    pop ebp
    ret

Please note that the above code is written in x86 assembly language and assumes that you have a compatible assembler and linker to compile and run it. The code uses the sprintf and printf functions to convert the value to a string and print it, respectively.